$But-1-ene \xrightarrow[(ii) NaBH_4]{(i) (CH_3COO)_2Hg/H_2O} ?$
The product in the above reaction is:

  • A
    $CH_3-CH_2-CH_2-CH_2-OH$
  • B
    $CH_3-CH_2-CH(OH)-CH_3$
  • C
    $CH_3=CH_2-CH(OH)-CH_3$
  • D
    $CH_3-CH_2=C(OH)-CH_3$

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