By the Remainder Theorem,find the remainder w | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to the Remainder Theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Given $g(x) = x - 3$,we set $g(x) = 0$ t

Vedclass · Accepted Answer

$62$

Vedclass · Answer

(C) According to the Remainder Theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Given $g(x) = x - 3$,we set $g(x) = 0$ to find the value of $x$:$x - 3 = 0 \Rightarrow x = 3$.Now,we substitute $x = 3$ into the polynomial $p(x)$:$p(3) = (3)^{3} - 3(3)^{2} + 4(3) + 50$$p(3) = 27 - 3(9) + 12 + 50$$p(3) = 27 - 27 + 12 + 50$$p(3) = 0 + 62 = 62$.Therefore,the remainder is $62$.

By the Remainder Theorem,find the remainder when $p(x)$ is divided by $g(x)$,where $p(x) = x^{3} - 3x^{2} + 4x + 50$ and $g(x) = x - 3$.

Similar Questions

Expand $(x+3)(x+8)$.

Find $p(1)$,$p(2)$,and $p(4)$ for the following polynomial:
$p(x) = x^{2} - 3x + 2$

Write the coefficient of $x^{2}$ in the following polynomial:
$4+7x+3x^{2}$

Evaluate $66 \times 74$ without directly multiplying.

Classify the following as a constant,linear,quadratic,or cubic polynomial: $t^{2}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module