By what angle should M_2 be rotated,so that t | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. The incident ray strikes mirror $M_1$ at an angle of incidence $i_1 = 90^{\circ} - 40^{\circ} = 50^{\circ}$.$2$. The reflected ray from $M_1$

Vedclass · Accepted Answer

$5^{\circ}$ clockwise

Vedclass · Answer

(A) $1$. The incident ray strikes mirror $M_1$ at an angle of incidence $i_1 = 90^{\circ} - 40^{\circ} = 50^{\circ}$.$2$. The reflected ray from $M_1$ makes an angle of $40^{\circ}$ with the horizontal.$3$. Let the angle of mirror $M_2$ with the horizontal be $\alpha = 25^{\circ}$. The angle of incidence at $M_2$ is $i_2 = 40^{\circ} + 25^{\circ} = 65^{\circ}$.$4$. For the final reflected ray to be horizontal,the angle of reflection at $M_2$ must be $r_2 = 0^{\circ}$ relative to the horizontal,meaning the ray must be parallel to the horizontal.$5$. If the mirror $M_2$ is rotated by an angle $	heta$,the new angle of the mirror with the horizontal becomes $\alpha'$. The angle of incidence at $M_2$ becomes $i_2' = 40^{\circ} + \alpha'$.$6$. For the reflected ray to be horizontal,the angle of the reflected ray with the mirror must be equal to the angle of incidence. Geometry shows that for the reflected ray to be horizontal,the angle of incidence at $M_2$ must be $20^{\circ}$.$7$. Thus,$40^{\circ} + \alpha' = 65^{\circ} - 	heta = 20^{\circ} \Rightarrow 	heta = 5^{\circ}$ clockwise.

By what angle should $M_2$ be rotated,so that the light ray after reflection from both mirrors becomes horizontal? (The angle of incidence at mirror $M_1$ is $40^{\circ}$ and the angle between $M_2$ and the horizontal is $25^{\circ}$ as shown in the figure.)

Similar Questions

Images formed by an object placed between two plane mirrors whose reflecting surfaces make an angle of $90^o$ with one another lie on

$A$ ray reflected successively from two plane mirrors inclined at a certain angle undergoes a deviation of $300^o$. The number of observable images is:

Light rays fall on a plane mirror and form a real image. Therefore,the incident rays are:

$A$ plane mirror produces a magnification of

$A$ man is $180\,cm$ tall and his eyes are $10\,cm$ below the top of his head. In order to see his entire height from toe to head,he uses a plane mirror kept at a distance of $1\,m$ from him. The minimum length of the plane mirror required is.....$cm$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module