By what factor does the average velocity of a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The formula for the average velocity $(V_{av})$ of a gaseous molecule is given by $V_{av} = \sqrt{\frac{8RT}{\pi M}}$.From this expression,it is c

Vedclass · Accepted Answer

$1.4$

Vedclass · Answer

(D) The formula for the average velocity $(V_{av})$ of a gaseous molecule is given by $V_{av} = \sqrt{\frac{8RT}{\pi M}}$.From this expression,it is clear that $V_{av} \propto \sqrt{T}$.When the temperature is doubled,the new temperature $T' = 2T$.Therefore,the ratio of the new average velocity to the initial average velocity is $\frac{V_{av}'}{V_{av}} = \sqrt{\frac{T'}{T}} = \sqrt{\frac{2T}{T}} = \sqrt{2} \approx 1.414$.Thus,the average velocity increases by a factor of approximately $1.4$.

By what factor does the average velocity of a gaseous molecule increase when the temperature (in Kelvin) is doubled?

Similar Questions

If the $RMS$ speed of nitrogen at a certain temperature is $3000 \ ms^{-1}$,the approximate kinetic energy of one mole of nitrogen at that temperature in $kJ$ is (assume nitrogen as ideal gas)

The ratio between the root mean square velocity of $H_2$ at $50 \ K$ and that of $O_2$ at $800 \ K$ is

The ratio between $RMS$ velocities of $H_2$ at $50 \ K$ and $O_2$ at $800 \ K$ is

The rms velocity $u_{rms}$,mean velocity $u_{av}$ and most probable velocity $u_{mp}$ of a gas differ from each other at a given temperature. Which of the following ratios regarding them is correct?

The most probable velocity is given by .......

Vedclass Test Series

Exam Paper Generator

Online Exam Module