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(D) In the $Wurtz$ reaction,alkyl halides react with $Na$ in the presence of dry ether to form alkanes. When a mixture of $CH_3I$ and $C_2H_5I$ is use

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$A$ mixture of the above three

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(D) In the $Wurtz$ reaction,alkyl halides react with $Na$ in the presence of dry ether to form alkanes. When a mixture of $CH_3I$ and $C_2H_5I$ is used,three different coupling reactions occur: $1. CH_3I + 2Na + ICH_3 \rightarrow CH_3-CH_3 (Ethane) + 2NaI$ $2. C_2H_5I + 2Na + IC_2H_5 \rightarrow C_2H_5-C_2H_5 (Butane) + 2NaI$ $3. CH_3I + 2Na + IC_2H_5 \rightarrow CH_3-C_2H_5 (Propane) + 2NaI$ Therefore,the product is a mixture of $Ethane$,$Propane$,and $Butane$.

Column-$I$	Column-$II$
$i$. $n$-Butane $\to 2$-methylpropane	$A$. Free radical substitution
$ii$. $CH_4 + Cl_2 \xrightarrow{hv} CH_3Cl + HCl$	$B$. Wurtz reaction
$iii$. $R-COONa \xrightarrow{\text{soda-lime}} R-H$	$C$. Isomerism
$iv$. $R-X + Na \xrightarrow{\text{Ether}} R-R$	$D$. Decarboxylation

By $Wurtz$ reaction,a mixture of $methyl \text{ } iodide$ and $ethyl \text{ } iodide$ gives:

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