Calculate $\Delta G^\circ$ for the conversion of oxygen to ozone $\frac{3}{2} O_{2(g)} \to O_{3(g)}$ at $298 \ K$,if $K_p$ for this conversion is $2.47 \times 10^{-29}$.

In an equilibrium reaction for which $\Delta G^o = 0$,the equilibrium constant $K = $

If the change in standard Gibbs free energy for a reaction is less than $0$,then the value of the equilibrium constant $K_c$ is:

At $298 \ K$, the equilibrium constant of the process $1.5 O_{2(g)} \rightleftharpoons O_{3(g)}$ is $3 \times 10^{-29}$. The standard free energy change (in $kJ \ mol^{-1}$) of the process is approximately ($R = 8.314 \ J \ mol^{-1} \ K^{-1}$; $\log 3 = 0.47$)

The standard Gibbs free energy change $\Delta G^o$ is related to the equilibrium constant $K_p$ as:

Consider the reaction $A \rightleftharpoons B$ at $1000 \ K$. At time $t^{\prime}$,the temperature of the system was increased to $2000 \ K$ and the system was allowed to reach equilibrium. Throughout this experiment,the partial pressure of $A$ was maintained at $1 \ bar$. Given below is the plot of the partial pressure of $B$ with time. What is the ratio of the standard Gibbs energy of the reaction at $1000 \ K$ to that at $2000 \ K$?