Calculate the frequency and wave number of a photon with a wavelength of $3.6 \ \mathring{A}$.
Given: Wavelength $(\lambda)$ = $3.6 \ \mathring{A} = 3.6 \times 10^{-10} \ m$.
Speed of light $(c)$ = $3 \times 10^{8} \ m/s$.
Frequency $(v)$ = $c / \lambda = (3 \times 10^{8} \ m/s) / (3.6 \times 10^{-10} \ m) = 8.333 \times 10^{17} \ s^{-1}$.
Wave number $(\bar{v})$ = $1 / \lambda = 1 / (3.6 \times 10^{-10} \ m) = 2.778 \times 10^{9} \ m^{-1}$.
Speed of light $(c)$ = $3 \times 10^{8} \ m/s$.
Frequency $(v)$ = $c / \lambda = (3 \times 10^{8} \ m/s) / (3.6 \times 10^{-10} \ m) = 8.333 \times 10^{17} \ s^{-1}$.
Wave number $(\bar{v})$ = $1 / \lambda = 1 / (3.6 \times 10^{-10} \ m) = 2.778 \times 10^{9} \ m^{-1}$.
Explore More
Similar Questions
Find the ratio of energy for radiations having $6000 \ \mathring{A}$ and $4000 \ \mathring{A}$ wavelength.
$(h = 6.62 \times 10^{-34} \ J \ s, c = 3 \times 10^8 \ m \ s^{-1})$
$(h = 6.62 \times 10^{-34} \ J \ s, c = 3 \times 10^8 \ m \ s^{-1})$
Medium
View SolutionElectromagnetic radiation with maximum wavelength is
Medium
View SolutionAssertion : All photons possess the same amount of energy.
Reason : Energy of photon does not depend upon wavelength of light used.
Reason : Energy of photon does not depend upon wavelength of light used.
MediumAIIMS 1998
View SolutionThe hydrogen spectrum from an incandescent source of hydrogen is:
Medium
View SolutionThe energy of an electromagnetic radiation is $19.875 \times 10^{-13} \ erg$. What is its wave number in $cm^{-1}$? $(h = 6.625 \times 10^{-27} \ erg \ sec, c = 3 \times 10^{10} \ cm \ sec^{-1})$
DifficultAP EAMCET 2002
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo