Calculate the boiling point of an aqueous sol | vedclass

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(B) Step $1$: Calculate the number of moles of glucose $(n)$: $n = \frac{	ext{mass}}{	ext{molar mass}} = \frac{18 	ext{ g}}{180 	ext{ g mol}^{-1}}

Vedclass · Accepted Answer

$100.5$

Vedclass · Answer

(B) Step $1$: Calculate the number of moles of glucose $(n)$: $n = \frac{	ext{mass}}{	ext{molar mass}} = \frac{18 	ext{ g}}{180 	ext{ g mol}^{-1}} = 0.1 	ext{ mol}$.Step $2$: Calculate the molality $(m)$ of the solution: $m = \frac{	ext{moles of solute}}{	ext{mass of solvent in kg}} = \frac{0.1 	ext{ mol}}{0.1 	ext{ kg}} = 1 	ext{ mol kg}^{-1}$.Step $3$: Calculate the elevation in boiling point $(\Delta T_b)$: $\Delta T_b = K_b 	imes m = 0.5 	ext{ K kg mol}^{-1} 	imes 1 	ext{ mol kg}^{-1} = 0.5 	ext{ K}$ (or $0.5^{\circ}	ext{C}$).Step $4$: Calculate the boiling point of the solution: $T_b = T_b^{\circ} + \Delta T_b = 100^{\circ}	ext{C} + 0.5^{\circ}	ext{C} = 100.5^{\circ}	ext{C}$.

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