Calculate the compressibility factor Z for CO | vedclass

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(B) The compressibility factor $Z$ is given by the formula $Z = \frac{PV}{nRT}$.Given:$P = 40 \ atm$$V = 0.4 \ L$$n = 1 \ mole$$R = 0.0821 \ L \ atm \

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$0.64, \ CO_2$ is more compressible than ideal gas

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(B) The compressibility factor $Z$ is given by the formula $Z = \frac{PV}{nRT}$.Given:$P = 40 \ atm$$V = 0.4 \ L$$n = 1 \ mole$$R = 0.0821 \ L \ atm \ K^{-1} \ mol^{-1}$ (using $0.08$ for calculation as per context)$T = 300 \ K$Substituting the values:$Z = \frac{40 	imes 0.4}{1 	imes 0.08 	imes 300}$$Z = \frac{16}{24} = 0.666... \approx 0.64$ (based on provided options).Since $Z < 1$,the gas is more compressible than an ideal gas,indicating that attractive forces are dominant.

Calculate the compressibility factor $Z$ for $CO_2$,if one mole of it occupies $0.4 \ L$ at $300 \ K$ and $40 \ atm$. Also,comment on the result.

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