Calculate the correct increasing order of ave | vedclass

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Question

(A) To find the average oxidation number of sulphur $(S)$ in each species:$1$. $S_8$: The oxidation state of an element in its standard state is $0$.$

Vedclass · Accepted Answer

$S_8 < S_2O_3^{2-} < S_4O_6^{2-} < SO_3^{2-} < S_2O_7^{2-}$

Vedclass · Answer

(A) To find the average oxidation number of sulphur $(S)$ in each species:$1$. $S_8$: The oxidation state of an element in its standard state is $0$.$2$. $S_2O_3^{2-}$: $2x + 3(-2) = -2 \implies 2x - 6 = -2 \implies 2x = 4 \implies x = +2$.$3$. $S_4O_6^{2-}$: $4x + 6(-2) = -2 \implies 4x - 12 = -2 \implies 4x = 10 \implies x = +2.5$.$4$. $SO_3^{2-}$: $x + 3(-2) = -2 \implies x - 6 = -2 \implies x = +4$.$5$. $S_2O_7^{2-}$: $2x + 7(-2) = -2 \implies 2x - 14 = -2 \implies 2x = 12 \implies x = +6$.Comparing the values: $0 The correct order is $S_8 < S_2O_3^{2-} < S_4O_6^{2-} < SO_3^{2-} < S_2O_7^{2-}$.

Calculate the correct increasing order of average oxidation number of sulphur in $S_8, S_2O_3^{2-}, S_2O_7^{2-}, S_4O_6^{2-}, SO_3^{2-}$

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