Calculate the mass of a divalent metal produced at the cathode by passing $5 \ A$ current through its salt solution for $100 \ minutes$. (Molar mass of metal $= x \ g/mol$)
- A$\frac{193}{30} x \ g$
- B$\frac{193}{15} x \ g$
- C$\frac{15}{193} x \ g$
- D$\frac{30}{193} x \ g$
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