Calculate the mean of the following data: | vedclass

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(B) Since the given data is not continuous,we first convert it into continuous class intervals by subtracting $0.5$ from the lower limit and adding $0

Vedclass · Accepted Answer

$12.93$

Vedclass · Answer

(B) Since the given data is not continuous,we first convert it into continuous class intervals by subtracting $0.5$ from the lower limit and adding $0.5$ to the upper limit of each class.Now,we calculate the class mark $x_{i}$ for each class and then proceed as follows:						Class			Class mark $(x_{i})$			Frequency $(f_{i})$			$f_{i} x_{i}$							$3.5-7.5$			$5.5$			$5$			$27.5$							$7.5-11.5$			$9.5$			$4$			$38$							$11.5-15.5$			$13.5$			$9$			$121.5$							$15.5-19.5$			$17.5$			$10$			$175$							Total			-			$\Sigma f_{i} = 28$			$\Sigma f_{i} x_{i} = 362$			Therefore,the mean $\bar{x} = \frac{\Sigma f_{i} x_{i}}{\Sigma f_{i}} = \frac{362}{28} \approx 12.93$.Hence,the mean of the given data is $12.93$.

Marks	Number of students
Below $10$	$10$
Below $20$	$50$
Below $30$	$130$
Below $40$	$270$
Below $50$	$440$
Below $60$	$570$
Below $70$	$670$
Below $80$	$740$
Below $90$	$780$
Below $100$	$800$

Calculate the mean of the following data:

Class $4-7$ $8-11$ $12-15$ $16-19$

Frequency $5$ $4$ $9$ $10$

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Calculate the mean of the following data: Class $4-7$ $8-11$ $12-15$ $16-19$ Frequency $5$ $4$ $9$ $10$