Calculate the molality of a solution of a non-volatile solute if the boiling point elevation is $1.75 \ K$ and the $K_b$ for the solvent is $3 \ K \ kg \ mol^{-1}$. (in $m$)

Arrange the following solutions in order of their increasing boiling points.
$(i) \ 10^{-4} \ M \ NaCl$ $(ii) \ 10^{-4} \ M \ \text{Urea}$ $(iii) \ 10^{-3} \ M \ NaCl$ $(iv) \ 10^{-2} \ M \ NaCl$

Calculate the number of moles of nonvolatile solute dissolved in $0.3 \ kg$ solvent if $\Delta T_{b}=0.3 \ K$ and $K_{b}$ for solvent is $1.8 \ K \ kg \ mol^{-1}$.

$5 \ g$ of a non-volatile organic substance with molar mass $M_A$ is dissolved in $200 \ g$ of tetrahydrofuran. If $K_b$ is the molal elevation constant of tetrahydrofuran,then $\Delta T_b$ will be:

The value of $K_b$ is given by $mRT_b^2 / 1000 \, X$. In this relation,$X$ is :-

Two different solutions were prepared by dissolving sucrose in water having concentrations of $1 \ m$ and $2 \ m$ respectively. The value of $(T_2 - T_1)$ will be ........... $K$. (Given: $K_b$ for water $= 0.52 \ K \ kg \ mol^{-1}$)