Calculate the mole fraction of benzene in a solution containing $30\%$ by mass in carbon tetrachloride.

Calculate the molality of $2.5 \ g$ of ethanoic acid $(CH_{3}COOH)$ in $75 \ g$ of benzene.

Dissolving $120 \ g$ of a compound (mol. wt $= 60$) in $1000 \ g$ of water gave a solution of density $1.12 \ g \ mL^{-1}$. The molarity of the solution is: (in $M$)

The mole fraction of a solute in a solution is $0.1$. At $298 \ K$,molarity of the solution is the same as its molality. The density of this solution at $298 \ K$ is $2.0 \ g \ cm^{-3}$. The ratio of the molecular weights of the solute and solvent,$\left(\frac{MW_{solute}}{MW_{solvent}}\right)$,is

Calculate the mass percentage of benzene $(C_{6}H_{6})$ and carbon tetrachloride $(CCl_{4})$ if $22 \ g$ of benzene is dissolved in $122 \ g$ of carbon tetrachloride.

The mole fraction of a solute in a $100$ molal aqueous solution is $.......... \times 10^{-2}$ (Round off to the nearest integer). [Given: Atomic masses: $H = 1.0 \ u$,$O = 16.0 \ u$]