Calculate the mole fraction of ethylene glyco | vedclass

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(A) Assume that we have $100 \ g$ of solution.Solution will contain $20 \ g$ of ethylene glycol and $80 \ g$ of water.Molar mass of $C_{2}H_{6}O_{2} =

Vedclass · Accepted Answer

$0.068$

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(A) Assume that we have $100 \ g$ of solution.Solution will contain $20 \ g$ of ethylene glycol and $80 \ g$ of water.Molar mass of $C_{2}H_{6}O_{2} = 12 	imes 2 + 1 	imes 6 + 16 	imes 2 = 62 \ g \ mol^{-1}$.Moles of $C_{2}H_{6}O_{2} = \frac{20 \ g}{62 \ g \ mol^{-1}} = 0.322 \ mol$.Moles of water = $\frac{80 \ g}{18 \ g \ mol^{-1}} = 4.444 \ mol$.Mole fraction of ethylene glycol $(x_{glycol})$ = $\frac{	ext{moles of } C_{2}H_{6}O_{2}}{	ext{moles of } C_{2}H_{6}O_{2} + 	ext{moles of } H_{2}O}$.$x_{glycol} = \frac{0.322}{0.322 + 4.444} = \frac{0.322}{4.766} = 0.068$.

Calculate the mole fraction of ethylene glycol $(C_{2}H_{6}O_{2})$ in a solution containing $20\%$ of $C_{2}H_{6}O_{2}$ by mass.

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