Calculate the molecular masses of C_2H_4,NH_3 | vedclass

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(A) $(i)$ Molecular mass of $C_2H_4$ (ethene):$= (	ext{Atomic mass of C} 	imes 2) + (	ext{Atomic mass of H} 	imes 4)$$= (12 	imes 2) + (1 	imes

Vedclass · Accepted Answer

$28\,u$,$17\,u$ and $32\,u$

Vedclass · Answer

(A) $(i)$ Molecular mass of $C_2H_4$ (ethene):$= (	ext{Atomic mass of C} 	imes 2) + (	ext{Atomic mass of H} 	imes 4)$$= (12 	imes 2) + (1 	imes 4) = 24 + 4 = 28\,u$.$(ii)$ Molecular mass of $NH_3$ (ammonia):$= (	ext{Atomic mass of N} 	imes 1) + (	ext{Atomic mass of H} 	imes 3)$$= (14 	imes 1) + (1 	imes 3) = 14 + 3 = 17\,u$.$(iii)$ Molecular mass of $CH_3OH$ (methanol):$= (	ext{Atomic mass of C} 	imes 1) + (	ext{Atomic mass of H} 	imes 4) + (	ext{Atomic mass of O} 	imes 1)$$= (12 	imes 1) + (1 	imes 4) + (16 	imes 1) = 12 + 4 + 16 = 32\,u$.

Calculate the molecular masses of $C_2H_4$,$NH_3$ and $CH_3OH$.

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