Calculate the number of protons,neutrons and | vedclass

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Question

(A) An element is represented as ${}_Z^A X$,where:$Z$ is the atomic number (number of protons).$A$ is the mass number (sum of protons and neutrons).Fo

Vedclass · Accepted Answer

$16, 16, 18$

Vedclass · Answer

(A) An element is represented as ${}_Z^A X$,where:$Z$ is the atomic number (number of protons).$A$ is the mass number (sum of protons and neutrons).For ${}_{16}^{32} S^{2-}$:Number of protons $= Z = 16$.Number of neutrons $= A - Z = 32 - 16 = 16$.Since the ion has a charge of $-2$,it has gained $2$ electrons.Number of electrons $= Z + 2 = 16 + 2 = 18$.Thus,the number of protons,neutrons,and electrons are $16, 16, 18$ respectively.The correct option is $A$ (or $D$ as they are identical).

$(i) \ _{26}Fe^{54}, \ _{26}Fe^{56}, \ _{26}Fe^{58}$	$(a) \ \text{Isotopes}$
$(ii) \ _1H^3, \ _2He^3$	$(b) \ \text{Isotones}$
$(iii) \ _{32}Ge^{76}, \ _{33}As^{77}$	$(c) \ \text{Isoelectronic}$
$(iv) \ _{92}U^{235}, \ _{90}Th^{231}$	$(d) \ \text{Isobars}$
$(v) \ _1H^1, \ _1D^2, \ _1T^3$

Calculate the number of protons,neutrons and electrons in ${}_{16}^{32} S^{2-}$.

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