Calculate the number of unit cells in $38.6 \ g$ of noble metal having density $19.3 \ g \ cm^{-3}$ and volume of one unit cell is $6.18 \times 10^{-23} \ cm^{3}$?
- A$3.236 \times 10^{22}$
- B$6.180 \times 10^{23}$
- C$6.236 \times 10^{20}$
- D$3.236 \times 10^{23}$
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