Calculate the partial pressure exerted by dio | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Step $1$: Calculate the number of moles of each gas.$n_{O_2} = \frac{32 \ g}{32 \ g/mol} = 1 \ mol$$n_{Ar} = \frac{80 \ g}{40 \ g/mol} = 2 \ mol$$

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(B) Step $1$: Calculate the number of moles of each gas.$n_{O_2} = \frac{32 \ g}{32 \ g/mol} = 1 \ mol$$n_{Ar} = \frac{80 \ g}{40 \ g/mol} = 2 \ mol$$n_{H_2} = \frac{4 \ g}{2 \ g/mol} = 2 \ mol$Step $2$: Calculate the total number of moles.$n_{	ext{total}} = n_{O_2} + n_{Ar} + n_{H_2} = 1 + 2 + 2 = 5 \ mol$Step $3$: Calculate the mole fraction of dioxygen $(x_{O_2})$.$x_{O_2} = \frac{n_{O_2}}{n_{	ext{total}}} = \frac{1}{5} = 0.2$Step $4$: Calculate the partial pressure of dioxygen $(P_{O_2})$.$P_{O_2} = x_{O_2} 	imes P_{	ext{total}} = 0.2 	imes 10 \ bar = 2 \ bar$

Calculate the partial pressure exerted by dioxygen from a mixture of $32 \ g$ $O_2$,$80 \ g$ $Ar$ (molar mass $40 \ g/mol$) and $4 \ g$ dihydrogen $(P_{\text{total}} = 10 \ bar)$. (in $bar$)

Similar Questions

What is the ratio of kinetic energy of $7 \ g$ of nitrogen and $4 \ g$ of oxygen at $T \ K$?

$A$ pressure cooker reduces the cooking time because:

$50 \ mL$ of hydrogen diffuses out through a small hole from a vessel in $20 \ min$. The time needed for $40 \ mL$ of oxygen to diffuse out is ............. $min$.

Equal volume of $2$ gases $A$ and $B$ diffuse in $20 \ s$ and $10 \ s$ respectively. If molar mass of $A$ is $80$,then the molar mass of $B$ is:

Mechanical work is especially important in systems that contain

Vedclass Test Series

Exam Paper Generator

Online Exam Module