Calculate the quantity of CO_2 required to pr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to Henry's law, $P = K_H 	imes x$, where $x$ is the mole fraction of $CO_2$. Given $P = 2 \,atm = 2 	imes 1.01325 	imes 10^5 \,Pa = 2

Vedclass · Accepted Answer

$2.9$

Vedclass · Answer

(C) According to Henry's law, $P = K_H 	imes x$, where $x$ is the mole fraction of $CO_2$. Given $P = 2 \,atm = 2 	imes 1.01325 	imes 10^5 \,Pa = 2.0265 	imes 10^5 \,Pa$. $K_H = 1.67 	imes 10^8 \,Pa$. $x = \frac{P}{K_H} = \frac{2.0265 	imes 10^5}{1.67 	imes 10^8} \approx 1.213 	imes 10^{-3}$. Since the amount of $CO_2$ is small, the number of moles of water in $1 \,L$ $(1000 \,g)$ is $n_{H_2O} = \frac{1000}{18} \approx 55.55 \,mol$. $x = \frac{n_{CO_2}}{n_{CO_2} + n_{H_2O}} \approx \frac{n_{CO_2}}{n_{H_2O}}$. $n_{CO_2} = x 	imes n_{H_2O} = 1.213 	imes 10^{-3} 	imes 55.55 \approx 0.0674 \,mol$. Mass of $CO_2 = n_{CO_2} 	imes 	ext{Molar mass} = 0.0674 	imes 44 \approx 2.96 \,g$. Rounding to the nearest provided option, the correct answer is $2.9 \,g$.

Calculate the quantity of $CO_2$ required to prepare $1 \,L$ of soda water when the soda water is packed under $2 \,atm$ of $CO_2$. [Henry's law constant for $CO_2$ is $1.67 \times 10^8 \,Pa$] (in $\,g$)

Similar Questions

Which of the following is a solution in which the physical states of solute and solvent are liquid and solid respectively?

Assertion: $A$ mixture of $He$ and $O_2$ is used for respiration for deep sea divers.
Reason: $He$ is soluble in blood.

The solubility of a gas in a liquid generally increases with :-

The Henry's law constant for the solubility of $N_2$ gas in water at $298 \ K$ is $1.0 \times 10^5 \ atm$. The mole fraction of $N_2$ in air is $0.8$. Calculate the number of moles of $N_2$ dissolved in $10 \ moles$ of water at $298 \ K$ and a total pressure of $5 \ atm$.

Explain the equilibrium of gases in liquids.

Vedclass Test Series

Exam Paper Generator

Online Exam Module