Calculate the solubility in $\text{mol dm}^{-3}$ of a sparingly soluble salt $BA$ at $293 \text{ K}$ if its solubility product constant $(K_{sp})$ is $8.56 \times 10^{-5}$ at the same temperature.

In qualitative analysis,the metals of group $I$ can be separated from other ions by precipitating them as chloride salts. $A$ solution initially contains $Ag^{+}$ and $Pb^{2+}$ at a concentration of $0.10 \, M$. Aqueous $HCl$ is added to this solution until the $Cl^{-}$ concentration is $0.10 \, M$. What will the concentrations of $Ag^{+}$ and $Pb^{2+}$ be at equilibrium? ($K_{sp}$ for $AgCl = 1.8 \times 10^{-10}$,$K_{sp}$ for $PbCl_2 = 1.7 \times 10^{-5}$)

At $20\,^oC$,the concentration of $Ag^{+}$ in a saturated solution of $Ag_2CrO_4$ is $1.5 \times 10^{-4}\,mol\,L^{-1}$. The solubility product of $Ag_2CrO_4$ at $20\,^oC$ is .......

The $K_{SP}$ of $AgI$ is $1.5 \times 10^{-16}$. On mixing equal volumes of the following solutions,precipitation will occur only with:

An acidified solution of $0.05 \ M \ Zn^{2+}$ is saturated with $0.1 \ M \ H_2S$. What is the minimum molar concentration $(M)$ of $H^{+}$ required to prevent the precipitation of $ZnS$? Use $K_{sp}(ZnS) = 1.25 \times 10^{-22}$ and overall dissociation constant of $H_2S$,$K_{NET} = K_1 K_2 = 1 \times 10^{-21}$.

The solubility products of three sparingly soluble salts are given below. What is the correct decreasing order of their molar solubility?

$S.No.$	$Formula$	$K_{sp}$
$1$	$PQ$	$4.0 \times 10^{-20}$
$2$	$PQ_2$	$3.2 \times 10^{-14}$
$3$	$PQ_3$	$2.7 \times 10^{-35}$