Calculate the solubility of sparingly soluble salt $BA$ in $mol \ dm^{-3}$ at $300 \ K$ if its solubility product is $4.9 \times 10^{-9}$ at same temperature.
- A$5.72 \times 10^{-5}$
- B$6.40 \times 10^{-5}$
- C$7.00 \times 10^{-5}$
- D$7.81 \times 10^{-5}$
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