Calculate the volume of a simple cubic unit cell if the radius of the particle in it is $400 \ pm$.
- A$6.36 \times 10^{-22} \ cm^3$
- B$5.12 \times 10^{-22} \ cm^3$
- C$5.84 \times 10^{-22} \ cm^3$
- D$6.60 \times 10^{-22} \ cm^3$
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Lithium crystallises into a body-centered cubic $(BCC)$ structure. What is the radius of lithium if the edge length of its unit cell is $351 \ pm$ (in $pm$)?
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View Solution$A$ metal crystallizes in a simple cubic lattice. The volume of one unit cell is $6.4 \times 10^7 \ pm^3$. What is the radius of the metal atom in $pm$?
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