Calculate the work done when 2 moles of an id | vedclass

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(C) The work done during expansion against a constant external pressure is given by the formula: $W = -P_{ext} \Delta V$. First,convert the volumes to

Vedclass · Accepted Answer

$-0.404$

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(C) The work done during expansion against a constant external pressure is given by the formula: $W = -P_{ext} \Delta V$. First,convert the volumes to the same unit $(m^3)$: $V_1 = 5 \ dm^3 = 5 	imes 10^{-3} \ m^3$. $V_2 = 7 	imes 10^{-3} \ m^3$. Change in volume: $\Delta V = V_2 - V_1 = (7 	imes 10^{-3} - 5 	imes 10^{-3}) \ m^3 = 2 	imes 10^{-3} \ m^3$. Now,calculate the work done: $W = -(2.02 	imes 10^5 \ Nm^{-2}) 	imes (2 	imes 10^{-3} \ m^3)$. $W = -4.04 	imes 10^2 \ J = -404 \ J$. Converting to $kJ$: $W = -0.404 \ kJ$.

Calculate the work done when $2$ moles of an ideal gas expand from a volume of $5 \ dm^3$ to $7 \times 10^{-3} \ m^3$ against a constant external pressure of $2.02 \times 10^5 \ Nm^{-2}$. (in $kJ$)

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