Calculate the volume of H_2 gas kept at STP i | vedclass

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Question

(A) Molar mass of $H_3PO_4 = (3 	imes 1) + 31 + (4 	imes 16) = 98 \ g/mol$.Given mass of $H_3PO_4 = 98 \ g$,so moles of $H_3PO_4 = 98/98 = 1 \ mol$.

Vedclass · Accepted Answer

$33.6$

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(A) Molar mass of $H_3PO_4 = (3 	imes 1) + 31 + (4 	imes 16) = 98 \ g/mol$.Given mass of $H_3PO_4 = 98 \ g$,so moles of $H_3PO_4 = 98/98 = 1 \ mol$.Each molecule of $H_3PO_4$ contains $3$ atoms of $H$.Therefore,total moles of $H$ atoms $= 1 \ mol 	imes 3 = 3 \ mol$ of $H$ atoms.Let the volume of $H_2$ gas at $STP$ be $V \ L$.Number of moles of $H_2$ gas $= V/22.4 \ mol$.Since each molecule of $H_2$ contains $2$ atoms of $H$,moles of $H$ atoms in $H_2$ gas $= 2 	imes (V/22.4) = V/11.2 \ mol$.Equating the moles of $H$ atoms: $V/11.2 = 3$.$V = 3 	imes 11.2 = 33.6 \ L$.

Calculate the volume of $H_2$ gas kept at $STP$ if it contains as many $H$ atoms as in $98 \ g$ of $H_3PO_4$. (Atomic mass of $P = 31 \ u$) (in $L$)

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