Carbon is present in the highest oxidation nu | vedclass

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(A) Let the oxidation number of carbon be $x$.For $CO_{3}^{2-}$: $x + 3(-2) = -2 \implies x - 6 = -2 \implies x = +4$.For $CaC_{2}$: $Ca^{2+} + 2x = 0

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$CO_{3}^{2-}$

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(A) Let the oxidation number of carbon be $x$.For $CO_{3}^{2-}$: $x + 3(-2) = -2 \implies x - 6 = -2 \implies x = +4$.For $CaC_{2}$: $Ca^{2+} + 2x = 0 \implies +2 + 2x = 0 \implies x = -1$.For $CO$: $x + (-2) = 0 \implies x = +2$.For $C_{2}O_{4}^{2-}$: $2x + 4(-2) = -2 \implies 2x - 8 = -2 \implies 2x = +6 \implies x = +3$.Comparing the values,the highest oxidation number of carbon is $+4$,which is present in $CO_{3}^{2-}$.

Carbon is present in the highest oxidation number in

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