The centre of the circle $(x - 3)^2 + (y - 4)^2 = 5$ is

Find the equation of the circle with center at $(0,0)$ and radius $r$.

If the equation of the circle having its centre in the second quadrant touches the coordinate axes and also the line $\frac{x}{5}+\frac{y}{12}=1$ is $x^2+y^2+2 \lambda x-2 \lambda y+\lambda^2=0$,then $\lambda=$

If the lines $x + y = 6$ and $x + 2y = 4$ are diameters of a circle whose diameter is $20$,then the equation of the circle is:

Find the equation of a circle passing through the origin and making intercepts of length $5$ on both axes.

Find the centre and radius of the circle $2x^{2} + 2y^{2} - x = 0$.