Cerium (Z = 58) is an important member of the | vedclass

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(A) Cerium $(Z = 58)$ has an electronic configuration of $[Xe] 4f^1 5d^1 6s^2$.It exhibits both $+3$ and $+4$ oxidation states.The $+4$ oxidation stat

Vedclass · Accepted Answer

The $+4$ oxidation state of cerium is not known in solutions

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(A) Cerium $(Z = 58)$ has an electronic configuration of $[Xe] 4f^1 5d^1 6s^2$.It exhibits both $+3$ and $+4$ oxidation states.The $+4$ oxidation state of cerium is well-known and stable in aqueous solutions,where it acts as a strong oxidizing agent.Therefore,the statement that the $+4$ oxidation state is not known in solutions is incorrect.

Cerium $(Z = 58)$ is an important member of the lanthanoids. Which of the following statements about cerium is incorrect?

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