Cerium (IV) has a noble gas configuration. Wh | vedclass

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(B) Cerium $(Ce)$ has an atomic number of $58$. Its electronic configuration is $[Xe] 4f^1 5d^1 6s^2$. In the $+4$ oxidation state,$Ce^{4+}$ has the c

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It will prefer to gain an electron and act as an oxidizing agent.

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(B) Cerium $(Ce)$ has an atomic number of $58$. Its electronic configuration is $[Xe] 4f^1 5d^1 6s^2$. In the $+4$ oxidation state,$Ce^{4+}$ has the configuration $[Xe]$,which is a stable noble gas configuration. However,$Ce^{4+}$ has a strong tendency to gain an electron to return to the more stable $+3$ oxidation state $(Ce^{3+})$. The reduction reaction is: $Ce^{4+} + e^- \rightarrow Ce^{3+} \quad E^0 = +1.61 \ V$. Since it readily accepts an electron,it acts as a strong oxidizing agent.

Cerium $(IV)$ has a noble gas configuration. Which of the following is the correct statement about it?

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