Charges Q, 2Q and -Q are given to three conce | vedclass

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(D) Let the charges on the shells be $Q_A = Q$,$Q_B = 2Q$,and $Q_C = -Q$.$1$. The inner surface of shell $A$ has $0$ charge,so the outer surface of $A

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$-\frac{3}{2}$

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(D) Let the charges on the shells be $Q_A = Q$,$Q_B = 2Q$,and $Q_C = -Q$.$1$. The inner surface of shell $A$ has $0$ charge,so the outer surface of $A$ has $Q$.$2$. The inner surface of shell $B$ must have a charge of $-Q$ to cancel the effect of the charge on shell $A$. Since the total charge on shell $B$ is $2Q$,the outer surface of $B$ has $2Q - (-Q) = 3Q$.$3$. The inner surface of shell $C$ must have a charge of $-3Q$ to cancel the effect of the charge on the outer surface of $B$. Since the total charge on shell $C$ is $-Q$,let the charge on the outer surface of $C$ be $q_{out}$.$4$. Thus,$-3Q + q_{out} = -Q$,which gives $q_{out} = 2Q$.$5$. The ratio of the charge on the inner surface to the charge on the outer surface of shell $C$ is $\frac{-3Q}{2Q} = -\frac{3}{2}$.

Charges $Q, 2Q$ and $-Q$ are given to three concentric conducting shells $A, B$ and $C$ respectively as shown. The ratio of charges on the inner and outer surfaces of shell $C$ will be:

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