Which of the following is a chiral complex? H | vedclass

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(A) complex is chiral if it lacks a plane of symmetry and a center of inversion. $cis-[PtCl_2(en)_2]^{2+}$ has a $cis$ configuration where the two $Cl

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$cis-[PtCl_2(en)_2]^{2+}$

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(A) complex is chiral if it lacks a plane of symmetry and a center of inversion. $cis-[PtCl_2(en)_2]^{2+}$ has a $cis$ configuration where the two $Cl$ atoms are adjacent. This structure lacks a plane of symmetry,making it optically active and chiral. $trans-[PtCl_2(en)_2]^{2+}$ has a plane of symmetry,so it is achiral. $cis-[PtCl_2(NH_3)_2]$ is a square planar complex,which is achiral. $trans-[Co(NH_3)_4Cl_2]^{+}$ has a plane of symmetry,so it is achiral.

$A$. Tetrahedral $NiCl_2Br_2^{2-}$	$B$. Square planar $Pt(NH_3)_2Cl_2$
$C$. Octahedral $Co(NH_3)_3Cl_3$	$D$. Square planar $Pd(NH_3)_3Br^{+}$
$E$. Octahedral $Co(en)_3^{3+}$

Complexes	No. of unpaired electrons
$A. [CrF_6]^{4-}$	$P. 5$
$B. [MnF_6]^{4-}$	$Q. 2$
$C. [Cr(CN)_6]^{4-}$	$R. 1$
$D. [Mn(CN)_6]^{4-}$	$S. 4$

Which of the following is a chiral complex? Here $en = \text{ethylenediamine}$.

Similar Questions

The complex that can exhibit linkage isomerism is

The type of isomerism which exists between $[Pd(C_6H_5)_2(SCN)_2]$ and $[Pd(C_6H_5)_2(NCS)_2]$ is

Which of the following molecules/ions can exhibit isomerism:
$A$. Tetrahedral $NiCl_2Br_2^{2-}$ $B$. Square planar $Pt(NH_3)_2Cl_2$
$C$. Octahedral $Co(NH_3)_3Cl_3$ $D$. Square planar $Pd(NH_3)_3Br^{+}$
$E$. Octahedral $Co(en)_3^{3+}$

Here,$en = 1,2-\text{diaminoethane}$.

Calculate the magnetic moment of the $Fe^{3+}$ ion in the $[Fe(CN)_6]^{3-}$ complex.

The correct match is:

Complexes No. of unpaired electrons

$A. [CrF_6]^{4-}$ $P. 5$

$B. [MnF_6]^{4-}$ $Q. 2$

$C. [Cr(CN)_6]^{4-}$ $R. 1$

$D. [Mn(CN)_6]^{4-}$ $S. 4$

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