Chloral + Chlorobenzene xrightarrow{conc. H_2 | vedclass

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Question

(B) The reaction between $Chloral$ $(CCl_3CHO)$ and $Chlorobenzene$ $(C_6H_5Cl)$ in the presence of concentrated $H_2SO_4$ is a condensation reaction.

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$DDT$

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(B) The reaction between $Chloral$ $(CCl_3CHO)$ and $Chlorobenzene$ $(C_6H_5Cl)$ in the presence of concentrated $H_2SO_4$ is a condensation reaction.Two molecules of $Chlorobenzene$ react with one molecule of $Chloral$ to eliminate a water molecule,forming $p,p'$-dichlorodiphenyltrichloroethane,commonly known as $DDT$.The reaction is:$CCl_3CHO + 2C_6H_5Cl \xrightarrow{conc. H_2SO_4} (ClC_6H_4)_2CHCCl_3 + H_2O$Thus,the product is $DDT$.

$Chloral + Chlorobenzene \xrightarrow{conc. H_2SO_4} \text{product}$.
The product is :-

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$Chloral + Chlorobenzene \xrightarrow{conc. H_2SO_4} \text{product}$.The product is :-