Choose the CORRECT comparison of decreasing p | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The $\pi -$ bond order is calculated by dividing the total number of $\pi -$ bonds by the total number of $S-O$ bonds in the resonance hybrid stru

Vedclass · Accepted Answer

$SO_3 > SO_4^{2-} > SO_3^{2-}$

Vedclass · Answer

(A) The $\pi -$ bond order is calculated by dividing the total number of $\pi -$ bonds by the total number of $S-O$ bonds in the resonance hybrid structure.						$Species$			$S-O$ $\pi -$ Bond order							$SO_3$			$1$							$SO_4^{2-}$			$0.5$							$SO_3^{2-}$			$0.33$			Thus,the decreasing order of $\pi -$ bond order is $SO_3 > SO_4^{2-} > SO_3^{2-}$.

Choose the $CORRECT$ comparison of decreasing $\pi -$ bond order of $S-O$ bond.

Similar Questions

Which of the following is the most stable canonical structure among all?

Determine the order of bond length for the $C-N$ bonds labeled as $x$,$y$,and $z$ in the given structures.

$(i)$ Draw the resonance structures of $N_2O_3$ and state its shape.
$(ii)$ Indicate the bond angles and bond lengths in it.

The correct order of increasing $C - O$ bond length of $CO, CO_3^{2-}, CO_2$ is

In $BF_3$ molecule:

Vedclass Test Series

Exam Paper Generator

Online Exam Module