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(A) To solve this,we count the total number of characters including blanks. The sequence is $...bbca...bcca...ac...a...cb$. Total characters = $20$. W

Vedclass · Accepted Answer

$abcba$

Vedclass · Answer

(A) To solve this,we count the total number of characters including blanks. The sequence is $...bbca...bcca...ac...a...cb$. Total characters = $20$. We can divide this into groups of $4$ ($20/4 = 5$ groups).Group $1$: $a b b c$Group $2$: $a b c c$Group $3$: $a b c a$Group $4$: $a c a c$Wait,let's try a different grouping. If we look at the pattern $abc a$,$bbca$,$bcca$,$acba$,$acbc$,it doesn't seem consistent.Let's try filling the blanks with option $C$ $(bacab)$:$b b b c a / a b c c a / b a c a / c a c b$This doesn't seem right. Let's re-examine the sequence: $a b b c a / a b c c a / a b c a / a c b a / c b$.Actually,the pattern is $abc a$ repeated with variations. Testing option $C$ $(bacab)$: $b b b c a / a b c c a / a b c a / a c b a / c b$. Still not quite right.Let's test option $A$ $(abcba)$: $a b b c a / b b c c a / a b c a / a c b a / c b$. This fits the pattern of repeating $abc$ sequences. The correct sequence is $abcba$.

Choose the correct alternative to complete the series: $...bbca...bcca...ac...a...cb$

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