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Question

(A) To solve this series,we look for a repeating pattern. The given series is $a . c a c b c . . . b a c a . . . b$.
By observing the sequence,we can

Vedclass · Accepted Answer

$baba$

Vedclass · Answer

(A) To solve this series,we look for a repeating pattern. The given series is $a . c a c b c . . . b a c a . . . b$.
By observing the sequence,we can identify a repeating block of $4$ letters: $acbc$.
Let's break the series into groups of $4$: $(acbc) (acbc) (acbc) (acbc)$.
Comparing this with the given series $a . c a c b c . . . b a c a . . . b$,we can see that the missing letters are $b, a, b, a$.
Therefore,the correct sequence is $abacbcacbcacbcacbc$.
The missing letters are $b, a, b, a$.

Choose the correct alternative to fill in the blanks for the series: $a . c a c b c . . . b a c a . . . b$

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