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Question

(A) To solve this,we count the total number of characters including blanks. The series is $...c...bd.....cbcda.....a...db...a$. There are $24$ positio

Vedclass · Accepted Answer

$adabed$

Vedclass · Answer

(A) To solve this,we count the total number of characters including blanks. The series is $...c...bd.....cbcda.....a...db...a$. There are $24$ positions in total. We look for a repeating pattern. By dividing the series into groups of $4$,we get: $(adbc) (adbc) (adbc) (adbc) (adbc) (adbc)$.Comparing this with the given series: $a d b c | a d b c | a d b c | a d b c | a d b c | a d b c$.The blanks are filled as follows:$a d b c | a d b c | a d b c | a d b c | a d b c | a d b c$.The missing letters are $a, d, a, b, e, d$. However,checking the pattern again,the correct sequence is $adbc$. Filling the blanks: $a d b c | a d b c | a d b c | a d b c | a d b c | a d b c$. The sequence of filled letters is $a, d, a, b, e, d$ which matches option $A$.

Choose the correct alternative to fill in the blanks in the series: $...c...bd.....cbcda.....a...db...a$

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