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Question

(A) To solve this,we look for a repeating pattern in the series: $....a...b...abaa...bab...abb$. By observing the sequence,we can divide it into group

Vedclass · Accepted Answer

$aaabb$

Vedclass · Answer

(A) To solve this,we look for a repeating pattern in the series: $....a...b...abaa...bab...abb$. By observing the sequence,we can divide it into groups of $3$: $baa / bba / baa / bba / baa / bb$. Filling the blanks with the missing letters: $1^{st}$ blank: $b$ $2^{nd}$ blank: $a$ $3^{rd}$ blank: $a$ $4^{th}$ blank: $b$ $5^{th}$ blank: $b$ Thus,the missing sequence is $baabb$.

Choose the correct alternative to complete the series: $....a...b...abaa...bab...abb$

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