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(B) The given set is $(256, 64, 16)$.Observing the pattern: $256 = 4^4$ or $2^8$,$64 = 4^3$ or $2^6$,and $16 = 4^2$ or $2^4$.Alternatively,each number

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$(144, 36, 9)$

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(B) The given set is $(256, 64, 16)$.Observing the pattern: $256 = 4^4$ or $2^8$,$64 = 4^3$ or $2^6$,and $16 = 4^2$ or $2^4$.Alternatively,each number is obtained by dividing the previous number by $4$: $256 / 4 = 64$ and $64 / 4 = 16$.Checking the options:Option $A$: $160 / 4 = 40$ and $40 / 4 = 10$. This follows the same pattern.Option $B$: $144 / 4 = 36$ and $36 / 4 = 9$. This also follows the same pattern.Option $C$: $80 / 4 = 20$ and $20 / 4 = 5$. This also follows the same pattern.However,looking at the powers of $4$ specifically: $256 = 4^4, 64 = 4^3, 16 = 4^2$.Option $B$ consists of $144 = 12^2, 36 = 6^2, 9 = 3^2$ (not powers of $4$).Option $A$ consists of $160, 40, 10$ (not powers of $4$).Option $C$ consists of $80, 20, 5$ (not powers of $4$).Re-evaluating the relation: The set $(256, 64, 16)$ represents $(4^4, 4^3, 4^2)$.Among the choices,$(144, 36, 9)$ represents $(12^2, 6^2, 3^2)$,which is a consistent geometric progression with a common ratio of $1/4$ is not present,but $144/4=36$ and $36/4=9$ is correct. Given the standard logic for such problems,$(144, 36, 9)$ is the most mathematically consistent set.

Choose the correct alternative for the given relation.
Given set: $(256, 64, 16)$

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Choose the correct alternative for the given relation.Given set: $(256, 64, 16)$