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(C) The Hershey-Chase experiment $(1952)$ was designed to determine whether $DNA$ or protein is the genetic material.$1$. They grew some bacteriophage

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Experiment - Bacteriophage,Radioactive $^{35}S$ labelled protein capsule; Conclusion - No radioactive $^{35}S$ detected in cells + Radioactive $^{35}S$ detected in supernatant.

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(C) The Hershey-Chase experiment $(1952)$ was designed to determine whether $DNA$ or protein is the genetic material.$1$. They grew some bacteriophages on a medium containing radioactive phosphorus $(^{32}P)$ to label their $DNA$,and others on a medium containing radioactive sulfur $(^{35}S)$ to label their protein coats.$2$. When the phages labelled with $^{35}S$ (protein) infected bacteria,the radioactivity remained in the supernatant after centrifugation,indicating that the protein did not enter the cell.$3$. When the phages labelled with $^{32}P$ $(DNA)$ infected bacteria,the radioactivity was detected inside the bacterial cells,proving that $DNA$ is the genetic material.$4$. Option $C$ correctly describes the result for the $^{35}S$ experiment: the radioactive protein coat remains outside the cell in the supernatant.

Choose the correct option for the conclusion of the Hershey-Chase experiment.

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