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(C) According to Fajan's rules,the covalent character of an ionic bond increases with the polarization of the anion. Polarization is favored by a smal

Vedclass · Accepted Answer

$LiF$ is more covalent than $KF$

Vedclass · Answer

(C) According to Fajan's rules,the covalent character of an ionic bond increases with the polarization of the anion. Polarization is favored by a smaller cation size and a larger anion size. Comparing $LiF$ and $KF$: $Li^+$ is smaller than $K^+$,so $Li^+$ has a higher polarizing power,making $LiF$ more covalent than $KF$. Comparing $KF$ and $KI$: $I^-$ is larger than $F^-$,so $KI$ is more covalent than $KF$. Comparing $SnCl_4$ and $SnCl_2$: $Sn^{4+}$ has a higher charge density than $Sn^{2+}$,making $SnCl_4$ more covalent. Comparing $ZnCl_2$ and $NaCl$: $Zn^{2+}$ has a pseudo-inert gas configuration ($18$ electrons in the valence shell),which is more polarizing than the inert gas configuration of $Na^+$,making $ZnCl_2$ more covalent than $NaCl$. Therefore,the correct statement is that $LiF$ is more covalent than $KF$.

Choose the correct option from the following regarding the covalent character of compounds.

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