Choose the correct order for the given properties.
- A$NaF < MgF_2 < AlF_3$ : covalent character order
- B$NaF < MgF_2 < AlF_3$ : melting point order
- C$NaF < MgF_2 < AlF_3$ : lattice energy order
- DAll of above are correct
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Similar Questions
Which one of the following is a correct set?
Compound $X$ is the anhydride of sulphuric acid. The number of $\sigma$-bonds and the number of $\pi$-bonds present in $X$ are,respectively:
What do you mean by strength and reactivity of a bond?
Easy
View SolutionThe correct order for $O-O$ bond length in the given substances is:
$I.$ $H_2O_2$
$II.$ $O_2$
$III.$ $O_3$
$I.$ $H_2O_2$
$II.$ $O_2$
$III.$ $O_3$
Medium
View SolutionMatch List-$I$ with List-$II$ and select the correct answer:
List-$I$ (Molecule / Species) List-$II$ $(P)$ $NO_2$ (Unpaired electron in) $(1)$ Vacant $p$-orbital involved in hybridization $(Q)$ $B_2H_6$ $(2)$ $sp^2$-orbital $(R)$ $ClO_3$ (Unpaired electron in) $(3)$ $sp^3$-orbital $(S)$ $CH_3^+$ $(4)$ $120^\circ$ Bond angle
| List-$I$ (Molecule / Species) | List-$II$ |
| $(P)$ $NO_2$ (Unpaired electron in) | $(1)$ Vacant $p$-orbital involved in hybridization |
| $(Q)$ $B_2H_6$ | $(2)$ $sp^2$-orbital |
| $(R)$ $ClO_3$ (Unpaired electron in) | $(3)$ $sp^3$-orbital |
| $(S)$ $CH_3^+$ | $(4)$ $120^\circ$ Bond angle |
Difficult
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