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(B) Statement $(a)$ is correct: $AgF$ is the only silver halide that is soluble in water due to high hydration energy of $F^-$ ion,and it is colourles

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$(a, b)$

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(B) Statement $(a)$ is correct: $AgF$ is the only silver halide that is soluble in water due to high hydration energy of $F^-$ ion,and it is colourless.Statement $(b)$ is incorrect: $LiF$ has a higher melting point than $NaF$ due to its smaller size and higher lattice energy. Solubility of $LiF$ is also lower due to high lattice energy.Statement $(c)$ is incorrect: $Rb_2SO_4$ is highly soluble in water,whereas $BaSO_4$ is practically insoluble due to high lattice energy.Statement $(d)$ is correct: $AgI$ is a yellow-coloured precipitate. When added to water,it remains as a suspension,giving the water a yellow appearance.Therefore,statements $(a)$ and $(d)$ are correct. However,based on the provided options,the most appropriate choice is $(b)$ $(a, b)$ is incorrect,but $(a, d)$ is not listed. Re-evaluating: $AgF$ is soluble $(a)$,$LiF$ solubility is lower than $NaF$ $(b)$,$Rb_2SO_4$ is more soluble than $BaSO_4$ $(c)$,$AgI$ is yellow $(d)$. The correct statements are $(a)$ and $(d)$. Since $(a, d)$ is not an option,and $(a, b)$ is provided,there is a discrepancy. Given standard chemistry,$(a)$ and $(d)$ are the factual statements.

Column-$I$ (Compound)	Column-$II$ (Products of heating effect)
$a$. $LiNO_3$	$P$. Metal oxide
$b$. $FeSO_4 \cdot 7H_2O$	$Q$. Paramagnetic gas
$c$. $NaHCO_3$	$R$. Acidic gas
$d$. $BeCO_3$	$S$. Evolved gas has same number of $\sigma$ and $\pi$ bonds

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