Choose the correct Zwitter ionic form for asp | vedclass

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Question

(B) Aspartic acid is an acidic amino acid with the structure $HOOC-CH(NH_2)-CH_2-COOH$. In its Zwitter ionic form,the proton from the $\alpha$-carboxy

Vedclass · Accepted Answer

The structure shows $H_3\stackrel{\oplus}{N}-CH(COOH)-COO^{\ominus}$.

Vedclass · Answer

(B) Aspartic acid is an acidic amino acid with the structure $HOOC-CH(NH_2)-CH_2-COOH$. In its Zwitter ionic form,the proton from the $\alpha$-carboxyl group $(-COOH)$ migrates to the amino group $(-NH_2)$ to form $-NH_3^{\oplus}$ and $-COO^{\ominus}$. Since aspartic acid has an additional carboxyl group in its side chain,the $\alpha$-carboxyl group is the most acidic and loses its proton first at physiological pH. Thus,the correct Zwitter ionic form is $H_3\stackrel{\oplus}{N}-CH(COO^{\ominus})-CH_2-COOH$.

Choose the correct Zwitter ionic form for aspartic acid.

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