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(C) The reaction of $CH_3-CH_2-CH=CH_2$ with $HBr$ in the presence of $H_2O_2$ (peroxide) follows the Kharasch effect or peroxide effect,which is an a

Vedclass · Accepted Answer

Instead of $HBr$,$HCl$ will also give the same reaction.

Vedclass · Answer

(C) The reaction of $CH_3-CH_2-CH=CH_2$ with $HBr$ in the presence of $H_2O_2$ (peroxide) follows the Kharasch effect or peroxide effect,which is an anti-Markovnikov addition.$1$. The major product formed is $CH_3-CH_2-CH_2-CH_2Br$ ($1$-bromobutane).$2$. $1$-bromobutane does not have a chiral carbon,so it does not show optical isomerism. Thus,option $A$ is correct.$3$. The mechanism involves free radical intermediates,so option $B$ is correct.$4$. The peroxide effect is specific to $HBr$ because the bond dissociation energy of $HCl$ is too high for the radical chain reaction to proceed,and $HI$ is too unstable. Therefore,$HCl$ does not undergo anti-Markovnikov addition in the presence of peroxide. Thus,option $C$ is incorrect.

Choose the incorrect option about the following reaction:
$CH_3-CH_2-CH=CH_2 \xrightarrow{HBr, H_2O_2}$

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Choose the incorrect option about the following reaction:$CH_3-CH_2-CH=CH_2 \xrightarrow{HBr, H_2O_2}$