Choose the incorrect order of bond length $-$

  • A
    $H_2 < F_2 < Cl_2$
  • B
    $H_2 < O_2 < Cl_2$
  • C
    $F_2 < Cl_2 < Br_2$
  • D
    $C-N < C-O < C-H$

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Similar Questions

Given below are two statements:
Statement $I$: $F_2O < H_2O < Cl_2O$ is the correct trend in terms of bond angle.
Statement $II$: $SiF_4, SnF_4$ and $PbF_4$ are ionic in nature.

$O-O$ bond length in $H_2O_2$ is $\underline{X}$ than the $O-O$ bond length in $F_2O_2$. The $O-H$ bond length in $H_2O_2$ is $Y$ than that of the $O-F$ bond in $F_2O_2$. Choose the correct option for $\underline{X}$ and $\underline{Y}$ from the given below.

The correct order of increasing bond length of $C - H, C - O, C - C$ and $C=C$ is

In the reaction $LiH + AlH_3 \to LiAlH_4$,$AlH_3$ and $LiH$ act as:

$X-O-X$ linkage is present in $[X = P/S/Cl/Mn]$:
$(a) P_2O_7^{4-}$
$(b) S_2O_5^{2-}$
$(c) S_2O_7^{2-}$
$(d) Cl_2O_7$
$(e) Mn_2O_7$
$(f) S_2O_8^{2-}$

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