(C) The mass of carbon in $2.64 \, g$ of $CO_2$ is: $m_C = \frac{12}{44} \times 2.64 = 0.72 \, g$.The mass of hydrogen in $1.08 \, g$ of $H_2O$ is: $m

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(C) The mass of carbon in $2.64 \, g$ of $CO_2$ is: $m_C = \frac{12}{44} \times 2.64 = 0.72 \, g$.The mass of hydrogen in $1.08 \, g$ of $H_2O$ is: $m_H = \frac{2}{18} \times 1.08 = 0.12 \, g$.The mass of oxygen in the compound is: $m_O = \text{Total mass} - (m_C + m_H) = 1.80 - (0.72 + 0.12) = 1.80 - 0.84 = 0.96 \, g$.The percentage of oxygen is: $\% \, O = \frac{0.96}{1.80} \times 100 = 53.33 \%$.

Class 11 Chemistry Some Basic Concepts of Chemistry Percentage composition and Molecular formula

Medium

Complete combustion of $1.80 \, g$ of an oxygen-containing compound $(C_xH_yO_z)$ gave $2.64 \, g$ of $CO_2$ and $1.08 \, g$ of $H_2O$. The percentage of oxygen in the organic compound is

JEE MAIN 2021 All JEE MAIN

A
$51.63$
B
$63.53$
C
$53.33$
D
$50.33$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

Some Basic Concepts of Chemistry

Subtopic

Percentage composition and Molecular formula

Previous Year

JEE MAIN 2021 Paper All JEE MAIN years →

$4 \ g$ of a hydrocarbon on complete combustion gave $12.571 \ g$ of $CO_2$ and $5.143 \ g$ of water. What is the empirical formula of the hydrocarbon?

MediumAP EAMCET 2002

View Solution

The formula for calcium chlorite is

EasyAIPMT 1996 AIPMT 1994

View Solution

Hemoglobin contains $0.334 \% \, Fe$ by weight. If the molecular mass of hemoglobin is approximately $67200 \, g/mol$,determine the number of iron atoms in one molecule of hemoglobin. (Atomic mass of $Fe = 56 \, g/mol$)

Difficult

View Solution

$A$ compound contains $2.2 \ g$ of phosphorus and $1.24 \ g$ of sulfur. What is its empirical formula?

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Complete combustion of $1.80 \, g$ of an oxygen-containing compound $(C_xH_yO_z)$ gave $2.64 \, g$ of $CO_2$ and $1.08 \, g$ of $H_2O$. The percentage of oxygen in the organic compound is

Similar Questions

$4 \ g$ of a hydrocarbon on complete combustion gave $12.571 \ g$ of $CO_2$ and $5.143 \ g$ of water. What is the empirical formula of the hydrocarbon?

The formula for calcium chlorite is

Hemoglobin contains $0.334 \% \, Fe$ by weight. If the molecular mass of hemoglobin is approximately $67200 \, g/mol$,determine the number of iron atoms in one molecule of hemoglobin. (Atomic mass of $Fe = 56 \, g/mol$)

$A$ compound contains $2.2 \ g$ of phosphorus and $1.24 \ g$ of sulfur. What is its empirical formula?

Vedclass Test Series

Exam Paper Generator

Online Exam Module