Complete reduction of benzene-diazonium chlor | vedclass

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Question

(B) The reduction of $benzene-diazonium$ chloride $(C_6H_5N_2Cl)$ with $Zn/HCl$ is a strong reduction process. It leads to the formation of $phenylhyd

Vedclass · Accepted Answer

Phenylhydrazine

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(B) The reduction of $benzene-diazonium$ chloride $(C_6H_5N_2Cl)$ with $Zn/HCl$ is a strong reduction process. It leads to the formation of $phenylhydrazine$ $(C_6H_5NHNH_2)$ as the final product. Note: While mild reducing agents like $SnCl_2/HCl$ or $Na_2SO_3$ can produce $phenylhydrazine$,strong reduction with $Zn/HCl$ also yields $phenylhydrazine$ as the primary product.

Complete reduction of $benzene-diazonium$ chloride with $Zn/HCl$ gives:

Similar Questions

The sequence of reagents required to convert aniline to benzoic acid is

The reaction is shown below. What is $X$ (major)?
$C_6H_5-CONH-C_6H_5 \xrightarrow{Br_2/Fe} X \text{ (major)}$

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Which of the following groups increases the basic strength of substituted aniline?

Which statement is not correct?

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