Complexes [Co(NH_3)_5SO_4]Br and [Co(NH_3)_5B | vedclass

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(D) The two complexes are ionization isomers.$1$. $[Co(NH_3)_5SO_4]Br$ ionizes in water to give $[Co(NH_3)_5SO_4]^+$ and $Br^-$ ions. The $Br^-$ ions

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(D) The two complexes are ionization isomers.$1$. $[Co(NH_3)_5SO_4]Br$ ionizes in water to give $[Co(NH_3)_5SO_4]^+$ and $Br^-$ ions. The $Br^-$ ions react with $AgNO_3$ to form a yellow precipitate of $AgBr$.$2$. $[Co(NH_3)_5Br]SO_4$ ionizes in water to give $[Co(NH_3)_5Br]^{2+}$ and $SO_4^{2-}$ ions. The $SO_4^{2-}$ ions react with $BaCl_2$ to form a white precipitate of $BaSO_4$.$3$. Conductance measurement: The first complex gives $2$ ions per formula unit,while the second complex gives $2$ ions per formula unit. However,the charge density and mobility of the ions differ,leading to different molar conductivities.Since all three methods can distinguish between these isomers,the correct answer is $D$.

Complexes $[Co(NH_3)_5SO_4]Br$ and $[Co(NH_3)_5Br]SO_4$ can be distinguished by

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