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(A) Compound $(X)$ reacts with $5$ moles of $H_2$,indicating $5$ $\pi$ bonds.The reaction with $AgNO_3$ to form a precipitate confirms the presence of

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$A$ structure showing a cyclohexadiene ring with a side chain $-CH=CH-C \equiv CH$

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(A) Compound $(X)$ reacts with $5$ moles of $H_2$,indicating $5$ $\pi$ bonds.The reaction with $AgNO_3$ to form a precipitate confirms the presence of a terminal alkyne $(-C \equiv CH)$.Reductive ozonolysis $(O_3/Me_2S)$ yields four fragments: $OHC-CH_2-CH_2-CO-CHO$ ($5$ carbons),$HOOC-CHO$ ($2$ carbons),$HCOOH$ ($1$ carbon),and $OHC-CHO$ ($2$ carbons).Reassembling these fragments based on the carbon count ($10$ carbons) and the degree of unsaturation leads to the structure $1-$vinyl$-2-$ethynyl$-1,3-$cyclohexadiene.The cleavage of the ring and side chains at the double and triple bonds matches the observed products.

Compound $(X)$ will be:
Compound $(X) \xrightarrow[Pt]{5H_2} \text{Saturated compound}$
Compound $(X) \xrightarrow{AgNO_3} \text{Precipitate}$
Compound $(X) \xrightarrow[Me_2S]{O_3} OHC-CH_2-CH_2-CO-CHO + HOOC-CHO + HCOOH + OHC-CHO$

Similar Questions

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The major product $'A'$ of the following given reaction has $......\,sp^2$ hybridized carbon atoms.
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Compound $(X)$ will be:Compound $(X) \xrightarrow[Pt]{5H_2} \text{Saturated compound}$Compound $(X) \xrightarrow{AgNO_3} \text{Precipitate}$Compound $(X) \xrightarrow[Me_2S]{O_3} OHC-CH_2-CH_2-CO-CHO + HOOC-CHO + HCOOH + OHC-CHO$