Compound (A) with molecular formula C_{11}H_8 | vedclass

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(C) $1$. The compound $(A)$ is $Ph-CH=CH-C \equiv C-CHO$. $2$. It does not undergo self-aldol condensation because the aldehyde group is conjugated wi

Vedclass · Accepted Answer

$Ph-CH=CH-C \equiv C-CHO$

Vedclass · Answer

(C) $1$. The compound $(A)$ is $Ph-CH=CH-C \equiv C-CHO$. $2$. It does not undergo self-aldol condensation because the aldehyde group is conjugated with a triple bond,reducing its electrophilicity and the acidity of $\alpha$-hydrogens. $3$. Ozonolysis of $Ph-CH=CH-C \equiv C-CHO$ gives $Ph-CHO$ and $OHC-C \equiv C-CHO$. $4$. The product $B$ is $OHC-C \equiv C-CHO$ (butenedial derivative). $5$. Oxidation of $B$ with $Ag^{+}$ (Tollens' reagent) yields oxalic acid $(HOOC-COOH)$.

Compound $(A)$ with molecular formula $C_{11}H_8O$ does not undergo self-aldol condensation. Upon ozonolysis,it yields $Ph-CHO$ and $2B$,where $B$ on oxidation with $Ag^{+}$ gives oxalic acid. Identify compound $(A)$.

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